7-(1/(16x^2))=0

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Solution for 7-(1/(16x^2))=0 equation: 


D( x )

16*x^2 = 0

16*x^2 = 0

16*x^2 = 0

16*x^2 = 0 // : 16

x^2 = 0

x = 0

x in (-oo:0) U (0:+oo)

7-(1/(16*x^2)) = 0

(-1/16)*x^-2+7 = 0

-1/16*x^-2 = -7 // : -1/16

x^-2 = 112

-2 < 0

1/(x^2) = 112 // * x^2

1 = 112*x^2 // : 112

1/112 = x^2

x^2 = 1/112 // ^ 1/2

abs(x) = (1/112)^(1/2)

x = (1/112)^(1/2) or x = -(1/112)^(1/2)

x in { (1/112)^(1/2), -(1/112)^(1/2) }

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